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CSIR NET & GATE Chemical Sciences

CSIR NET Coordination & Organometallic Chemistry Handwritten Notes (Free PDF)

Master the most crucial, high-weightage unit of Inorganic Chemistry. Download complete topper-curated class notes covering CFSE formulas, Jahn-Teller distortion, 18-electron counting rules, Wade’s clusters, and catalytic mechanisms.

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📊 1. Syllabus Breakdown & Exam Weightage

In CSIR UGC NET Chemical Science and GATE (CY), Inorganic Chemistry accounts for roughly 60 to 75 marks. Coordination compounds along with organometallic chemistry consistently contribute 35 to 45 marks across Part B and Part C.

Module NameQuestion TypeExpected MarksHigh-Frequency Core Topics
Coordination ChemistryPart B (2 marks) & Part C (4 marks)18 – 24 MarksCFT, CFSE, Spinels, Electronic spectra (Orgel & Tanabe-Sugano), Magnetic properties, Trans effect
Organometallic ChemistryPart B & Part C16 – 22 Marks18-electron counting, M−M bonds, Wade’s rules, Isolobal analogy, Wilkinson & Wacker catalysis
Reaction MechanismsPart C (Analytical)8 – 12 MarksInner-sphere vs Outer-sphere ET, Dissociative (D) & Associative (A) pathways

🔬 2. Coordination Chemistry: Key Formulas & Series

A. Octahedral vs. Tetrahedral Crystal Field Splitting

In octahedral complexes, d-orbitals split into degenerate t2g (stabilized by −0.4 Δo) and eg (destabilized by +0.6 Δo). In tetrahedral fields, the order inverts without the “g” subscript:

CFSE (Octahedral) = [(−0.4 × nt2g) + (0.6 × neg)] Δo + mP
Tetrahedral Splitting Relationship: Δt = (4/9) Δo ≈ 0.44 Δo
B. Spectrochemical Series of Ligands (Must Memorize)

I < Br < S2− < SCN < Cl < NO3 < F < OH < C2O42− < H2O < NCS < edta4− < NH3 < en < bipy < phen < NO2 < PPh3 < CN ≈ CO

C. Trans Effect (Kinetic Directing Ability in Square Planar Pt(II))

CN ≈ CO ≈ C2H4 > PR3 ≈ H > CH3 > C6H5 > I ≈ SCN > Br > Cl > Py > NH3 > OH > H2O

⚡ 3. Jahn-Teller Distortion (JTD) Reference Matrix

The Jahn-Teller theorem dictates that non-linear molecules with orbitally degenerate ground states distort to lower overall symmetry and lift degeneracy:

ConfigurationSpin StateElectronic OccupancyDistortion TypeRepresentative Example
d1, d2High / Lowt2g1, t2g2Weak (Dynamic JTD)[Ti(H2O)6]3+
d3, d8High / Lowt2g3, t2g6eg2No Distortion[Cr(H2O)6]3+, [Ni(H2O)6]2+
d4 (HS)High-Spint2g3eg1Strong (Static JTD)[Cr(H2O)6]2+, [Mn(H2O)6]3+
d7 (LS)Low-Spint2g6eg1Strong (Static JTD)[Co(NH3)6]2+
d9High / Lowt2g6eg3Very Strong (Tetragonal z-out)[Cu(H2O)6]2+
Pro-Tip for CSIR NET: In [Cu(H2O)6]2+, the z-out distortion (axial elongation) puts two electrons in dz2 and one in dx2y2, achieving greater energy stabilization (−½δ1) than the compressed z-in geometry.

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⚙️ 4. Organometallic Chemistry: 18-Electron Rule

A. Neutral vs. Ionic Ligand Electron Counting Table
LigandFormulaNeutral (Covalent) MethodIonic (Charge) Method
Terminal Halide / Hydride−X, −H1 e2 e (X, H)
Bridging Halideμ2−X3 e4 e (X)
Carbonyl / Phosphine−CO, −PR32 e2 e (neutral)
Nitrosyl (Linear)−NO (180°)3 e2 e (NO+)
Nitrosyl (Bent)−NO (≈ 120°)1 e2 e (NO)
Allyl Systemη1-allyl / η3-allyl1 e / 3 e2 e / 4 e (anion)
Cyclopentadienylη5-C5H5 (Cp)5 e6 e (Cp)
B. Formulas for Metal-Metal (M−M) Bonds
Total Valence Electrons (TVE) = Σ(Metal valence e) + Σ(Ligand e) ± Complex charge
Total M−M Bonds = [18 × n − TVE] / 2
M−M Bonds Per Metal Atom = 18 − (TVE / n)

🔷 5. Wade-Mingos Rules & Skeletal Electron Pairs

To classify metal cluster and borane architectures (where n = number of vertices/metal atoms):

Structure ClassificationSkeletal Electron Pairs (SEP)Formula FrameworkPolyhedron Geometry
Closon + 1BnHn2−Complete deltahedron (e.g., Octahedron, Icosahedron)
Nidon + 2BnHn+4Closo cage missing 1 vertex
Arachnon + 3BnHn+6Closo cage missing 2 vertices
Hyphon + 4BnHn+8Closo cage missing 3 vertices
Kladon + 5BnHn+10Closo cage missing 4 vertices

🔄 6. Industrial Catalysis: Reaction Cycles Comparison

Catalytic NameCatalyst / Active FormKey Elementary StepsCrucial Rate-Determining Step
Wilkinson’s HydrogenationRhCl(PPh3)3 → [RhCl(PPh3)2] (14 e)Oxidative Addition of H2 → Alkene coordination → Migratory insertion → Reductive eliminationMigratory insertion of hydride into coordinated alkene
Monsanto Acetic Acid[Rh(CO)2I2] (16 e)Oxidative addition of CH3I → CO migratory insertion → Reductive elimination of acetyl iodideOxidative addition of methyl iodide (CH3I) to Rh(I)
Wacker Oxidation[PdCl4]2− / CuCl2Ethylene coordination → Nucleophilic OH attack → β-hydride elimination → Reductive eliminationReoxidation of Pd(0) to Pd(II) by Cu(II) co-catalyst
Hydroformylation (Oxo)HRh(CO)(PPh3)3 or HCo(CO)4Alkene coordination → Insertion into M−H → CO insertion → Hydrogenolysis (Acyl to Aldehyde)Hydrogenolysis / Reductive elimination of aldehyde product

📝 7. Solved CSIR NET Part-C Practice Question

CSIR NET Chemical Science (Part C — 4 Marks)

Question: Find the total number of Metal−Metal (M−M) bonds in the cluster [Co4(CO)12] and the number of bonds per cobalt atom.

Step-by-Step Solution:

  1. Calculate Total Valence Electrons (TVE):
    Cobalt (Group 9) × 4 atoms = 4 × 9 = 36 e
    Carbonyl (−CO) ligands = 12 × 2 = 24 e
    TVE = 36 + 24 = 60 e
  2. Apply the M−M bond formula for n = 4 metal atoms:
    Total M−M Bonds = [18 × n − TVE] / 2 = [18(4) − 60] / 2 = [72 − 60] / 2 = 6 M−M Bonds.
  3. Calculate M−M bonds per metal atom:
    Bonds per metal = 18 − (TVE / n) = 18 − (60 / 4) = 18 − 15 = 3 Bonds/Metal.

Conclusion: [Co4(CO)12] forms a tetrahedral metal core with 6 total Co−Co edges, where each Cobalt atom is bonded to 3 neighbors.

❓ 8. Frequently Asked Questions (FAQs)

Q1: Are these handwritten notes sufficient to qualify CSIR NET Chemical Science?

Yes. These notes cover the entire syllabus for Coordination and Organometallic Chemistry. Once you thoroughly master the mechanisms and formulas in these notes, complement your study by solving the past 10 years of CSIR NET and GATE PYQs.

Q2: How do I identify whether a Nitrosyl (NO) ligand is linear or bent?

A linear M−N−O bond angle (180°) donates 3 electrons in the neutral method (NO+ donor), whereas a bent M−N−O bond angle (~120°) donates 1 electron (NO donor). Examine infrared IR stretching frequencies: linear NO absorbs at ~1800–1900 cm−1, while bent NO absorbs at ~1525–1650 cm−1.

Q3: What is the difference between Trans Effect and Trans Influence?

Trans influence is a ground-state thermodynamic property reflected in longer metal-ligand bond lengths (measured via X-ray crystallography). Trans effect is a kinetic property reflecting substitution rates influenced by stabilization of the trigonal bipyramidal transition state via π-backbonding.

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